Energy of a Cart on an Inclined Plane - top energy bars
A car of mass m = 1.2 kg is placed horizontally on a path that is tilted at an angle θ = 30 degrees. Cart rolls with very little friction and attaches above the rails by a spring with negligible mass, spring constant k = 20.0 N / m, and the United Nations extended length 25.0 cm.
(A) the use of energy in order to examine to determine whether the equilibrium position of the vehicle is at the top of the line.
(B) The car moves 7.5 cm over the hill from its equilibrium position, then released from rest. Draw a sketch of the situation along the hill to shopping with respect to its resting position against the time t after it is released.
(C) the traction energy) graphs (with real values, which lay the (kinetic and potential spring and gravity) of energy:
a. When released
b. If it through its equilibrium position
c. When you shut down.
(D) instead of lifting the mass, the second year led the way to what in its equilibrium position with a velocity v = 0.2 m released / s. Draw a sketchBody height and weight from its resting position against the time t after the release and use it to find T to (Y).
Thursday, January 21, 2010
Top Energy Bars Energy Of A Cart On An Inclined Plane
2 comments:
a)
F = ma = 1.25 (9.81) without (30) = 5.89 N
k = 20.0 N / m
f = kx
5.89 = 20x
x = 294 m, in addition to the original distance
x =. 250 + 294 = 0544 meters
b)
v = 1 / (2 * pi) (k / m) ^ 0.5
v = 1 / (2 * pi) (20/1.2) 0.50 = 0.634 sec / cycle
That up to 7.5 cm = 0, half way through all WY decline throughout the cycle t.
c) u = 1 / 2 kx ^ 2
Their full potential at t = o, and is part of the ceiling. Everything is in the Eastern kinetics
= 1 / 2 20 (7.5/100) ^ 2 = 1.41 A
a)
F = ma = 1.25 (9.81) without (30) = 5.89 N
k = 20.0 N / m
f = kx
5.89 = 20x
x = 294 m, in addition to the original distance
x =. 250 + 294 = 0544 meters
b)
v = 1 / (2 * pi) (k / m) ^ 0.5
v = 1 / (2 * pi) (20/1.2) 0.50 = 0.634 sec / cycle
That up to 7.5 cm = 0, half way through all WY decline throughout the cycle t.
c) u = 1 / 2 kx ^ 2
Their full potential at t = o, and is part of the ceiling. Everything is in the Eastern kinetics
= 1 / 2 20 (7.5/100) ^ 2 = 1.41 A
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